y^2-35y+304=0

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Solution for y^2-35y+304=0 equation:



y^2-35y+304=0
a = 1; b = -35; c = +304;
Δ = b2-4ac
Δ = -352-4·1·304
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-3}{2*1}=\frac{32}{2} =16 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+3}{2*1}=\frac{38}{2} =19 $

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